Logarithm is Big O Of Any Positive Power

Theorem

For any ϵ>0, ln(x)<xϵ for sufficiently large x, and hence log(x)=O(xϵ).

Proof

From L'Hopital's rule, we have

limxln(x)xϵ=limxx1ϵxϵ1=limx1ϵxϵ=0

because ϵ>0.

As such, there exists an x0 such that

x>x0ln(x)xϵ<1ln(x)<xϵ.

Any logarithm differs from the natural logarithm by a constant, and hence the above proves log(x)=O(xϵ).